Swift version: 5.6
Swift’s type safety means code to multiply an integer and a double won’t compile:
let a = 4
let b = 5.0
let c = a * b
You can either fix this by forcing your integer to be a double:
let d: Double = 4
let e = 5.0
let f = a * b
Alternatively you can convert your integer to a double as needed:
let g = 4
let h = 5.0
let i = Double(a) * b
If this situation really annoys you and you want it solved fully, add this custom *
function:
func *(lhs: Int, rhs: Double) -> Double {
return Double(lhs) * rhs
}
That will multiply an integer on the left with a double on the right, returning a double containing the result.
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This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
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