When talking about force unwrapping, I used this code:
let str = "5"
let num = Int(str)
That converts a string to an integer, but because you might try to pass any string there what you actually get back is an optional integer.
This is a failable initializer: an initializer that might work or might not. You can write these in your own structs and classes by using init?()
rather than init()
, and return nil
if something goes wrong. The return value will then be an optional of your type, for you to unwrap however you want.
As an example, we could code a Person
struct that must be created using a nine-letter ID string. If anything other than a nine-letter string is used we’ll return nil
, otherwise we’ll continue as normal.
Here’s that in Swift:
struct Person {
var id: String
init?(id: String) {
if id.count == 9 {
self.id = id
} else {
return nil
}
}
}
SPONSORED Alex is the iOS & Mac developer’s ultimate AI assistant. It integrates with Xcode, offering a best-in-class Swift coding agent. Generate modern SwiftUI from images. Fast-apply suggestions from Claude 3.5 Sonnet, o3-mini, and DeepSeek R1. Autofix Swift 6 errors and warnings. And so much more. Start your 7-day free trial today!
Sponsor Hacking with Swift and reach the world's largest Swift community!
Link copied to your pasteboard.