Failable initializers

When talking about force unwrapping, I used this code:

let str = "5"
let num = Int(str)

That converts a string to an integer, but because you might try to pass any string there what you actually get back is an optional integer.

This is a failable initializer: an initializer that might work or might not. You can write these in your own structs and classes by using init?() rather than init(), and return nil if something goes wrong. The return value will then be an optional of your type, for you to unwrap however you want.

As an example, we could code a Person struct that must be created using a nine-letter ID string. If anything other than a nine-letter string is used we’ll return nil, otherwise we’ll continue as normal.

Here’s that in Swift:

struct Person {
    var id: String

    init?(id: String) {
        if id.count == 9 {
            self.id = id
        } else {
            return nil
        }
    }
}

SPONSORED From August 2nd to 8th you can join a FREE crash course for mid/senior iOS devs who want to achieve an expert level of technical and practical skills – it’s the fast track to being a complete senior developer!

Save your spot now

Sponsor Hacking with Swift and reach the world's largest Swift community!