I'm trying to use Grid() to create a two-column Image() layout using ForEach, with a array of objects passed into the ForEach which has different lengths each time.

However, I'm having trouble wrapping my mind around the concept of doing this within a GridRow() item. The Issue is that ForEach only returns one item per iteration, which creates a new row for each. I've considered using something where I index the array and look at the next item to render it in that same GridRow, but that seems sloppy and clunky. Am I approaching this incorrectly?

I'm looking to achieve something like this:

Use a LazyVGrid, which will start in the top left and fill items horizontally in a row until it can't fit any more, then will wrap down to a second row, etc. You wouls just loop through your items with one ForEach and SwiftUI will take care of laying out the grid for you.

The screenshot above does use a LazyVGrid, but I'm trying to move away from that because of many issues I'm having with it, the main one being:

It's very difficult and time consuming to save and resume scroll state

I'd prefer the eager gris so I can have a absolute size I can scroll to to restore the user's place in the scroll when they navigate away from the view and/or app

I agree, there should be a way to do this using the new Grid(), rather than a Lazy grid. But what's the best way of laying out the objects without keeping a pointer to which object is next?