NEW: Subscribe to Hacking with Swift+ and accelerate your learning! >>

inout parameters

All parameters passed into a Swift function are constants, so you can’t change them. If you want, you can pass in one or more parameters as inout, which means they can be changed inside your function, and those changes reflect in the original value outside the function.

For example, if you want to double a number in place – i.e., change the value directly rather than returning a new one – you might write a function like this:

func doubleInPlace(number: inout Int) {
    number *= 2
}

To use that, you first need to make a variable integer – you can’t use constant integers with inout, because they might be changed. You also need to pass the parameter to doubleInPlace using an ampersand, &, before its name, which is an explicit recognition that you’re aware it is being used as inout.

In code, you’d write this:

var myNum = 10 
doubleInPlace(number: &myNum)
Hacking with Swift is sponsored by NSSpain

SPONSORED Announcing NSSpain 2020: Remote Edition! An online, continuous conference for iOS developers. We’ll start on Thursday and finish on Friday, with talks, activities, and lots of fun for 36 hours, non-stop. Sound good? Join us!

Find out more

Sponsor Hacking with Swift and reach the world's largest Swift community!

BUY OUR BOOKS
Buy Pro Swift Buy Swift Design Patterns Buy Testing Swift Buy Hacking with iOS Buy Swift Coding Challenges Buy Swift on Sundays Volume One Buy Server-Side Swift (Vapor Edition) Buy Advanced iOS Volume One Buy Advanced iOS Volume Two Buy Advanced iOS Volume Three Buy Hacking with watchOS Buy Hacking with tvOS Buy Hacking with macOS Buy Dive Into SpriteKit Buy Swift in Sixty Seconds Buy Objective-C for Swift Developers Buy Server-Side Swift (Kitura Edition) Buy Beyond Code

Was this page useful? Let us know!

Average rating: 4.6/5

Link copied to your pasteboard.