UPGRADE YOUR SKILLS: Learn advanced Swift and SwiftUI on Hacking with Swift+! >>

Use new .onChange modifier with Picker

Forums > SwiftUI

@frios  

I have a Picker setup as a segmented control which modifies a property in an environment object. When that property is modified, I would like to use the new .onChange modifier to set a local binding's value.

    @EnvironmentObject var tvm: TrucksViewModel
    @Binding var slideoverPosition: CGFloat

...

         //status picker
         Picker(selection: $tvm.status, label: Text("Status")) {
               Text("All").tag("All")
                Text("Scheduled").tag("Scheduled")
                Text("Live").tag("Live")
           }
           .onChange (of: tvm.status) {
                  pickerChanged()
            }
            .pickerStyle(SegmentedPickerStyle())

When I include the .onChange modifier I can't seem to figure out what the proper value of the of: parameter should be. I have tried tvm.status and $tvm.status but I keep getting an error like:

Cannot convert value of type 'String' to expected argument type '()'

Not sure how to fix this. Any help would be appreciated.

3      

@frios  

Solution found!

                        .onChange(of: tvm.status, perform: { (value) in
                            pickerChanged()
                        })

6      

Hacking with Swift is sponsored by Superwall

SPONSORED Superwall lets you build & test paywalls without shipping updates. Run experiments, offer sales, segment users, update locked features and more at the click of button. Best part? It's FREE for up to 250 conversions / mo and the Superwall team builds out 100% custom paywalls – free of charge.

Learn More

Sponsor Hacking with Swift and reach the world's largest Swift community!

Archived topic

This topic has been closed due to inactivity, so you can't reply. Please create a new topic if you need to.

All interactions here are governed by our code of conduct.

 
Unknown user

You are not logged in

Log in or create account
 

Link copied to your pasteboard.