Hello.

Is there a simple clean way to add an action to a toggle control in SwiftUI.

Sorry is this one has been answered before. I'm sure it must have but can't find anything.

Not sure what action you want to do with a Toggle

Taken from Apple Developer Documentation - Toggle

You create a toggle by providing an isOn binding and a label. Bind isOn to a Boolean property that determines whether the toggle is on or off. Set the label to a view that visually describes the purpose of switching between toggle states.

@State private var vibrateOnRing = false

var body: some View {
    Toggle(isOn: $vibrateOnRing) {
        Text("Vibrate on Ring")
    }
}

I'm looking at having an action like a button with code dependent on the state of the toggle.

You can use an onChange handler observing the same state variable you are using for the Toggle.

struct Toggler: View {
    @State private var vibrateOnRing = false

    var body: some View {
        Toggle(isOn: $vibrateOnRing) {
            Text("Vibrate on Ring")
        }
        .onChange(of: vibrateOnRing) { value in
            //perform your action here...
            print(value)
        }
    }
}

Hi everyone,

Just would to add another reply cause using .onChange is available only on iOS 14 and up, here it is my way of dealing with same question :

struct ContentView: View {
    @State private var isToggle : Bool = false {
            didSet {
                print("value did change")
            }
    }

    var body: some View {
        Toggle(isOn: self.$isToggle){
                    Text("Toggle Label ")
         }
    }
}