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SOLVED: How to style picker choices

Forums > SwiftUI

I have a picker (Destination is a String, CaseIterable enum) and getTabTitle returns a String:

            Picker(selection: $which, label: Image(systemName: "text.justify").font(.title) 
                    .frame(width: 50, height: 20, alignment: .trailing)) {
                ForEach(Destination.allCases, id: \.self) {
                    Text(getTabTitle($0)).foregroundColor(Color(UIColor.systemBlue))
                }
            }
            .pickerStyle(MenuPickerStyle())

The foregroundColor modifier is ignored: the menu items are drawn in black on a white background (or vice versa). How do I style the choices? (and is there a better symbol for a menu than the four horizontal lines of the text.justify system image?)

Jeremy

2      

I'm not sure that this is truly "solved", but I gather from elsewhere that it simply isn't possible without writing one's own Picker. Ah well. Maybe one day.

2      

Did you try to change the .accentColor of the Picker (not the Text)? Sometimes .accentColor is the way to go.

4      

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