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SOLVED: I cannot see Expected expression error

Forums > Swift

I have a function to handle interruptions such as phone calls, the game continues after the call but the background music does not. I keep getting Expected expression error but I cannot see any missing parenthesis or curly brackets.

    func handleInterruption(notification: Notification){
    guard let userInfo = notification.userInfo,
        let typeInt = userInfo[AVAudioSessionInterruptionTypeKey] as? UInt else{return}
    let type = AVAudioSession.InterruptionType(rawValue: typeInt); else do {return}      //expression error showing here.

    switch type{

    case .began:
        print("began")

        audioPlayer?.pause()
        print("audio paused")

    default:
        print("ended")

        if let optionInt = userInfo[AVAudioSessionInterruptionOptionKey] as? UInt {
            let options = AVAudioSession.InterruptionOptions(rawValue: optionInt)
            if options.contains(.shouldResume){}
            }
            }}

   

Change:

let type = AVAudioSession.InterruptionType(rawValue: typeInt); else do {return}

to:

guard let type = AVAudioSession.InterruptionType(rawValue: typeInt) else {return} 

   

Thanks for that, that has stopped the error. Much appreciated.

   

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