## SOLVED: Question : Please see my two simple sets of Structure. Which one is better ?

 Feb '22 Hello, I've been practicing. Please see my two sets of codes. Both are structures for creating Player, and both could work. It seems Code 2 is neater ? ( is it common to use closure in a property ?) Code 1 `````` struct Player { let name: String let number: Int init (name:String){ self.name = name number = Int.random(in: 1...99) } } let playerA = Player(name: "Paul") print(playerA.number) `````` Code 2 `````` struct Player { let name: String var number: Int { Int.random(in: 1...99)} } let playerA = Player(name:"Paul") print(playerA.number) `````` Thank you in advance, Boat Feb '22 The two structs are not quite the same. In the second struct, `number` is a computed variable that will be recalculated every time it is accessed. Adjust your test code to this and then try it with each of your `Player` structs and you will see what I mean: ``````let playerA = Player(name:"Paul") print(playerA.number) print(playerA.number) print(playerA.number) print(playerA.number) print(playerA.number) print(playerA.number)`````` 1 Feb '22 Oh `@roosterboy`, i just tested the code above, I got your point: in code 2, it is computed property, so the created instance `playerA` won't have a fixed number, right? but in code 1, once the instance is created, `playerA` will have a fixed number, right ? Boat Feb '22 in code 2, it is computed property, so the created instance `playerA` won't have a fixed number, right? but in code 1, once the instance is created, `playerA` will have a fixed number, right ? Yup. 1 Feb '22 Forgot to mention... This achieves what you were probably trying to do with the second `Player` struct: ``````struct Player { let name: String let number = Int.random(in: 1...99) }`````` You don't need an `init` since the default memberwise `init` provided by Swift will give you all you need. 1 Feb '22 Hm... `@roosterboy`, in your code `let number = Int.random(in: 1...99)`, Even if I change `let` to `var`, the value assigned to `number` from `Int.random` will still remain the same for the instance, right ? It won't generate a new random value everytime the instance is called. Right ? Feb '22 Correct, because it is assigned when the struct is created. If you use a `var` instead of a `let`, you'll be able to change the value later but until/unless you do so, the property will maintain its initial value. 1 Feb '22 Very clear now. Thank you `@roosterboy`

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