Swift version: 5.2
Here's a simple extension to UIColor
that lets you create colors from hex strings. The new method is a failable initializer, which means it returns nil if you don't specify a color in the correct format. It should be a # symbol, followed by red, green, blue and alpha in hex format, for a total of nine characters. For example, #ffe700ff is gold.
Here's the code:
extension UIColor {
public convenience init?(hex: String) {
let r, g, b, a: CGFloat
if hex.hasPrefix("#") {
let start = hex.index(hex.startIndex, offsetBy: 1)
let hexColor = String(hex[start...])
if hexColor.count == 8 {
let scanner = Scanner(string: hexColor)
var hexNumber: UInt64 = 0
if scanner.scanHexInt64(&hexNumber) {
r = CGFloat((hexNumber & 0xff000000) >> 24) / 255
g = CGFloat((hexNumber & 0x00ff0000) >> 16) / 255
b = CGFloat((hexNumber & 0x0000ff00) >> 8) / 255
a = CGFloat(hexNumber & 0x000000ff) / 255
self.init(red: r, green: g, blue: b, alpha: a)
return
}
}
}
return nil
}
}
If you wanted it always to return a value, change init?
to be init
then change the return nil
line at the end to be return UIColor.black
or whatever you'd like the default value to be.
To use the extension, write code like this:
let gold = UIColor(hex: "#ffe700ff")
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Available from iOS 2.0
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
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