How to run code after a delay using asyncAfter() and perform()
Swift version: 5.0
There are two ways to run code after a delay using Swift: GCD and perform(_:with:afterDelay:), but GCD has the advantage that it can run arbitrary blocks of code, whereas the perform() method runs methods.
DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
// your code here
}An alternative option is to use perform(_:with:afterDelay:), which lets you specify a method to call after a certain time has elapsed – and helpfully that time is specified in seconds, which makes it easier to remember!
To call the yourCodeHere() method after 1 second, you would use this code:
perform(#selector(yourCodeHere), with: nil, afterDelay: 1)SPONSOR Tired of wasting time debugging your Swift app? Instabug’s SDK is here to help you minimize your debugging time by providing you with complete device details, network logs, and reproduction steps with every bug report. All data is attached automatically. It only takes a line of code to setup. Get started for free.
Available from iOS 4.0
Did this solution work for you? Please pass it on!
Other people are reading…
- How to generate a random identifier using UUID
- How to cache data using NSCache
- How to identify an iOS device uniquely with identifierForVendor
- How to use Core Motion to read accelerometer data
- How to read names in a string using NSLinguisticTagger
About the Swift Knowledge Base
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
