How to open a URL in Safari
Swift version: 5.6
If you want the user to exit your app and show a website in Safari, it's just one line of code in Swift. I'll make it three here because I'll create the URL in the code too, then safely unwrap it:
if let url = URL(string: "https://www.hackingwithswift.com") {
UIApplication.shared.open(url)
}It's worth adding that you have the option of using SFSafariViewController inside your app, which recreates the entire Safari experience right inside your app. See Hacking with Swift project 32 for a tutorial on how to do this.
SPONSORED Play is the first native iOS design tool created for designers and engineers. You can install Play for iOS and iPad today and sign up to check out the Beta of our macOS app with SwiftUI code export. We're also hiring engineers!
Sponsor Hacking with Swift and reach the world's largest Swift community!
Available from iOS 10.0
Similar solutions…
- How to open web links in Safari
- How to make your app open with a custom URL scheme
- What does the open keyword do?
- How to open a new window
- How to load a remote image from a URL
About the Swift Knowledge Base
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
