How to open a URL in Safari
If you want the user to exit your app and show a website in Safari, it's just one line of code in Swift. I'll make it three here because I'll create the URL in the code too, then safely unwrap it:
if let url = URL(string: "https://www.hackingwithswift.com") {
UIApplication.shared.open(url, options: [:])
}It's worth adding that since iOS 9 you have the option of using SFSafariViewController inside your app, which recreates the entire Safari experience right inside your app. See Hacking with Swift project 32 for a tutorial on how to do this.
Available from iOS 2.0
Did this solution work for you? Please pass it on!
Other people are reading…
- How to download files with URLSession and downloadTask()
- How to spell out numbers using NumberFormatter's spellOut style
- How to create a peer-to-peer network using the multipeer connectivity framework
- How to copy objects in Swift using copy()
- How to run code when your app is terminated
About the Swift Knowledge Base
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
Take Swift further!
Your Swift skills let you make apps for macOS, watchOS, tvOS, and more, and for one low price you can learn it all with my Swift Platform Pack!
