Swift version: 5.10
If you want the user to exit your app and show a website in Safari, it's just one line of code in Swift. I'll make it three here because I'll create the URL in the code too, then safely unwrap it:
if let url = URL(string: "https://www.hackingwithswift.com") {
UIApplication.shared.open(url)
}
It's worth adding that you have the option of using SFSafariViewController
inside your app, which recreates the entire Safari experience right inside your app. See Hacking with Swift project 32 for a tutorial on how to do this.
SPONSORED Take the pain out of configuring and testing your paywalls. RevenueCat's all new Paywall Editor allow you to remotely configure your paywall view without any code changes or app updates.
Sponsor Hacking with Swift and reach the world's largest Swift community!
Available from iOS 10.0
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
Link copied to your pasteboard.