How to open a URL in Safari
Swift version: 5.6
If you want the user to exit your app and show a website in Safari, it's just one line of code in Swift. I'll make it three here because I'll create the URL in the code too, then safely unwrap it:
if let url = URL(string: "https://www.hackingwithswift.com") {
UIApplication.shared.open(url)
}It's worth adding that you have the option of using SFSafariViewController inside your app, which recreates the entire Safari experience right inside your app. See Hacking with Swift project 32 for a tutorial on how to do this.
SPONSORED Want to explore your Swift skill outside of the Apple world? Join the MadMachine community and start to program microcontrollers in Swift.
Sponsor Hacking with Swift and reach the world's largest Swift community!
Available from iOS 10.0
Similar solutions…
- How to open web links in Safari
- How to make your app open with a custom URL scheme
- What does the open keyword do?
- How to load a remote image from a URL
- How to load a string from a website URL
About the Swift Knowledge Base
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
