How to open a URL in Safari
Swift version: 5.1
If you want the user to exit your app and show a website in Safari, it's just one line of code in Swift. I'll make it three here because I'll create the URL in the code too, then safely unwrap it:
if let url = URL(string: "https://www.hackingwithswift.com") {
UIApplication.shared.open(url)
}It's worth adding that you have the option of using SFSafariViewController inside your app, which recreates the entire Safari experience right inside your app. See Hacking with Swift project 32 for a tutorial on how to do this.
LEARN SWIFTUI FOR FREE I have a massive, free SwiftUI video collection on YouTube teaching you how to build complete apps with SwiftUI – check it out!
Available from iOS 2.0
Similar solutions…
- How to make your app open with a custom URL scheme
- What does the open keyword do?
- How to load a string from a website URL
- How to load a remote image URL into UIImageView
- How to detect a URL in a String using NSDataDetector
About the Swift Knowledge Base
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
