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How to open a URL in Safari

Swift version: 5.2

Paul Hudson    @twostraws   

If you want the user to exit your app and show a website in Safari, it's just one line of code in Swift. I'll make it three here because I'll create the URL in the code too, then safely unwrap it:

if let url = URL(string: "https://www.hackingwithswift.com") {
    UIApplication.shared.open(url)
}

It's worth adding that you have the option of using SFSafariViewController inside your app, which recreates the entire Safari experience right inside your app. See Hacking with Swift project 32 for a tutorial on how to do this.

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Available from iOS 2.0

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