BLACK FRIDAY SALE: Save big on all my Swift books and bundles! >>

How to loop over non-nil items in an array

Swift version: 5.6

Paul Hudson    @twostraws   

Consider an array of items containing some optionals, like this one:

let numbers: [Int?] = [1, nil, 3, nil, 5]

If you want to loop over all the items and print them out, you’d write something like this:

for number in numbers {
    print(number)
}

However, that prints out all items in their current state: optionally wrapped integers for some, nil for others.

With a small change to that loop, you can have Swift unwrap all the optionals then only enter the loop for any that contain a value – any nil items are ignored. This is done using for case let syntax, like this:

for case let number? in numbers {
    print(number)
}

That will print the numbers 1, 3, and 5.

Hacking with Swift is sponsored by RevenueCat

SPONSORED In-app subscriptions are a pain to implement, hard to test, and full of edge cases. RevenueCat makes it straightforward and reliable so you can get back to building your app. Oh, and it's free if your app makes less than $10k/mo.

Learn more

Sponsor Hacking with Swift and reach the world's largest Swift community!

Available from iOS – learn more in my book Pro Swift

Similar solutions…

About the Swift Knowledge Base

This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.

BUY OUR BOOKS
Buy Pro Swift Buy Pro SwiftUI Buy Swift Design Patterns Buy Testing Swift Buy Hacking with iOS Buy Swift Coding Challenges Buy Swift on Sundays Volume One Buy Server-Side Swift Buy Advanced iOS Volume One Buy Advanced iOS Volume Two Buy Advanced iOS Volume Three Buy Hacking with watchOS Buy Hacking with tvOS Buy Hacking with macOS Buy Dive Into SpriteKit Buy Swift in Sixty Seconds Buy Objective-C for Swift Developers Buy Beyond Code

Was this page useful? Let us know!

Average rating: 5.0/5

 
Unknown user

You are not logged in

Log in or create account
 

Link copied to your pasteboard.