How to generate a random number
Swift version: 5.0
You can generate random numbers by calling the random() method on whatever numeric type you’re using, providing the range you want to work with. For example, this generates a random number in the range 1 through 5, inclusive on both sides:
let randomInt = Int.random(in: 1...5)Similar methods exist for Double, Float, and CGFloat:
let randomDouble = Double.random(in: 1...100)
let randomFloat = Float.random(in: 1..<10)
let randomCGFloat = CGFloat.random(in: 1...1000)There’s also one for booleans, generating true or false randomly:
let randomBool = Bool.random()Checking a random boolean is effectively the same as checking Int.random(in: 0...1) == 1, but it helps clarify your intent.
SPONSOR Tired of wasting time debugging your Swift app? Instabug’s SDK is here to help you minimize your debugging time by providing you with complete device details, network logs, and reproduction steps with every bug report. All data is attached automatically. It only takes a line of code to setup. Get started for free.
Available from iOS 8.0 – see Hacking with Swift tutorial 35
Did this solution work for you? Please pass it on!
Other people are reading…
- How to write a closure that returns a value
- How to use conditional conformance in Swift
- How to use map() with an optional value
- How to convert a String to Data
- How to check whether an integer lies inside a range
About the Swift Knowledge Base
This is part of the Swift Knowledge Base, a free, searchable collection of solutions for common iOS questions.
