TEAM LICENSES: Save money and learn new skills through a Hacking with Swift+ team license >>

Opening existential arguments to optional parameters

Available from Swift 5.8

Paul Hudson      @twostraws

SE-0375 extends a Swift 5.7 feature that allowed us to call generic functions using a protocol, fixing a small but annoying inconsistency: Swift 5.7 would not allow this behavior with optionals, whereas Swift 5.8 does.

For example, this code worked great in Swift 5.7, because it uses a non-optional T parameter:

func double<T: Numeric>(_ number: T) -> T {
    number * 2
}

let first = 1
let second = 2.0
let third: Float = 3

let numbers: [any Numeric] = [first, second, third]

for number in numbers {
    print(double(number))
}

In Swift 5.8, that same parameter can now be optional, like this:

func optionalDouble<T: Numeric>(_ number: T?) -> T {
    let numberToDouble = number ?? 0
    return  numberToDouble * 2
}

for number in numbers {
    print(optionalDouble(number))
}

In Swift 5.7 that would have issued the rather baffling error message “Type 'any Numeric' cannot conform to 'Numeric’”, so it’s good to see this inconsistency resolved.

Hacking with Swift is sponsored by Blaze.

SPONSORED Still waiting on your CI build? Speed it up ~3x with Blaze - change one line, pay less, keep your existing GitHub workflows. First 25 HWS readers to use code HACKING at checkout get 50% off the first year. Try it now for free!

Reserve your spot now

Sponsor Hacking with Swift and reach the world's largest Swift community!

Other changes in Swift 5.8…

Download all Swift 5.8 changes as a playground Link to Swift 5.8 changes

Browse changes in all Swift versions

 
Unknown user

You are not logged in

Log in or create account
 

Link copied to your pasteboard.